Multiple Function Arguments

Every function in Python receives a predefined number of arguments, if declared normally, like this:

def foo(first, second, third, *therest):
   print("First: %s" %(first))
   print("Second: %s" %(second))
   print("Third: %s" %(third))
   print("And all the rest... %s" %(list(therest)))                                                                                                                                     foo(1, 2, 3, 4, 5)

Output :

First: 1
Second: 2
Third: 3
And all the rest... [4, 5]

It is also possible to send functions arguments by keyword, so that the order of the argument does not matter, using the following syntax. The following code yields the following output: The sum is: 6 Result: 1

def bar(first, second, third, **options):
   if options.get("action") == "sum":
       print("The sum is: %d" %(first + second + third))

   if options.get("number") == "first":
       return first

result = bar(1, 2, 3, action = "sum", number = "first")
print("Result: %d" %(result))

Output :

The sum is: 6
Result: 1